本文目录一览：

• 1、c语言例子 100行以上

• 2、c语言 求100以内素数

• 3、用C语言求100以内的素数

• 4、求C语言编程实例100行以上，要有文字大概解释一下

c语言例子 100行以上

#include "stdafx.h"

#include "iostream.h"

#define M 2000

#define N 8

void magic(int a[M][M], int);

int main(int argc, char* argv[])

static int a[M][M];

int d = 12;

int n = 8;

while(1){

while(1)

cout"请输入方阵的阶数, 阶数必须能被4整除：";

cinn;

if(n%4 != 0 )cout"笨蛋,看清楚题目!\n"endl;

else if(n64)coutn"! 这么大， 想累死我啊， 不给算了!\n"endl;

else break;

//Init

for(int i=1; i=n; i++)

for(int j=1; j=n; j++)

a[i][j]=d;

d++;

// d++;

magic(a, n);

//Print dimension and sum for rows

for( i=1; i=n; i++)

int sum=0;

for(int j=1; j=n; j++)

couta[i][j]"\t";

sum+=a[i][j];

cout" | "sum"\n\n";

//Print sum of columns

for(i = 1; i=n; i++)cout"--\t";

cout"\n";

for(i=1; i=n; i++)

int sum = 0;

for(int j = 1; j=n; j++) sum += a[j][i];

coutsum"\t";

cout"\n\n";

char c;

cout"Continue?(y/n)";

cin c;

if(c=='n'|| c=='N')break;

return 0;

void exchg(int a, int b)

int t;

t = a;

a = b;

b = t;

void magic(int a[M][M], int n) // a:= 矩阵 n:= 实际阶数

int baseBlock_x=0;

int baseBlock_y=0;

int MaxBlock = n/4;

if(MaxBlock%2==0)

for(int bx = 0; bxMaxBlock/2; bx++)

for(int by=0; byMaxBlock; by++)

for(int c = 1; c = 4; c++)

exchg(a[bx*4+c][by*4+c], a[n+1-bx*4-c][n+1-by*4-c]);

exchg(a[bx*4+c][by*4+5-c], a[n+1-bx*4-c][n+1-by*4-5+c]);

else

for(int bx = 0; bxMaxBlock/2; bx++)

for(int by=0; byMaxBlock; by++)

for(int c = 1; c = 4; c++)

exchg(a[bx*4+c][by*4+c], a[n+1-bx*4-c][n+1-by*4-c]);

exchg(a[bx*4+c][by*4+5-c], a[n+1-bx*4-c][n+1-by*4-5+c]);

bx = MaxBlock/2;

for(int by=0; byMaxBlock; by++)

for(int c = 1; c = 2; c++)

exchg(a[bx*4+c][by*4+c], a[n+1-bx*4-c][n+1-by*4-c]);

exchg(a[bx*4+c][by*4+5-c], a[n+1-bx*4-c][n-by*4-4+c]);

c语言 求100以内素数

#includestdio.h

void main() { int m,n,i,j,b;

  scanf("%d%d",m,n);

  for ( i=m;i=n;i++ ) {

    b=1; for ( j=2;j=i/2;j++ ) if ( i%j==0 ) { b=0;break; }

    if ( b ) printf("%d ",i);

  printf("\n");

用C语言求100以内的素数

#includestdio.h

int main()

int i,k,n;

printf("请输入一个整数:");

scanf("%d",n); //输入 n 范围上限

printf("1~%d的素数为:\n",n);

for(i=2;i=n;i++) //外循环 从2到n 查找

for(k=2;k=i;k++) //内循环 将i除以 2到 i的所有值

if(i%k==0) //i能整除 其中一个数就不是素数 跳出内循环

break;

if(k=i) //k=i如果成立 说明前面循环结束时应为 k=i不满足 或 k=i是break

//跳出循环 这两种情况都说明 2到i所有的数都不能被i整除 （除了自身）

printf("%8d\n",i); //满足就输出这个素数

printf("\n");

return 0;

求C语言编程实例100行以上，要有文字大概解释一下

#include stdio.h

main(int a,char **date)

int year=0,month=0,day=0,week;

int d,i,dm,dy,m2;

char WEEK[9];

if (a==1)

printf ("\n ERROR! you forgot to enter the date you want to view\n");

exit (0);

i=0; d=-1;

while (date[1][i])/*遍历传入的参数日期，计算出year，month，day*/

if ((date[1][i]=='/'||date[1][i]=='.')d==-1) { d=0; i++; continue; }

if ((date[1][i]=='/'||date[1][i]=='.')d==0) { d=1; i++; continue; }

if (d==-1) year=year*10+(date[1][i]-'0');

if (d==0) month=month*10+(date[1][i]-'0');

if (d==1) day=day*10+(date[1][i]-'0');

i++;

if (month1||month12)/*若月份传入错误数字*/

printf ("\n ERROR! the entered MONTH is invalid\n");

exit (0);

if (year==2000)

dy=0; /*年引起的星期差为0个*/

m2=1; /*2月引起的星期差为1个*/

goto la_100;

if (year2000)

d=(year-1-2000)/4-(year-1-2000)/100+(year-1-2000)/400+1;

else

d=(year-2000)/4-(year-2000)/100+(year-2000)/400;

dy=(year-2000)+d; /*** 该年 1月1号 到2000年1月1号的 " 星期差 " ***/

if((year%4==0year%100!=0)||(year%100==0year%400==0))

m2=1;

else

m2=0; /*** 该年是否润 ***/

la_100: /**** la_100 ****/

/*** 该月以前的月所引起的 " 星期差 " ***/

switch (month)

case 1: dm=0; month=31; break; /*** month 在此存放该月天数 ***/

case 2: dm=3; month=d==1? 29:28; break;

case 3: dm=3+m2; month=31; break;

case 4: dm=6+m2; month=30; break;

case 5: dm=1+m2; month=31; break;

case 6: dm=4+m2; month=30; break;

case 7: dm=6+m2; month=31; break;

case 8: dm=2+m2; month=31; break;

case 9: dm=5+m2; month=30; break;

case 10: dm=m2; month=31; break;

case 11: dm=3+m2; month=30; break;

case 12: dm=5+m2; month=31; break;

if (day0||daymonth)

printf ("\n ERROR! the entered DAY is invalid\n");

exit (0);

week=(dy+dm+day-1+6)%7;

if(week0)

week+=7;

if (day0) /*** 判定查看类型 ***/

switch (week)

case 0: strcpy (WEEK,"SUNDAY"); break;

case 1: strcpy (WEEK,"MONDAY"); break;

case 2: strcpy (WEEK,"TUESDAY"); break;

case 3: strcpy (WEEK,"WEDNESDAY"); break;

case 4: strcpy (WEEK,"THURSDAY"); break;

case 5: strcpy (WEEK,"FRIDAY"); break;

case 6: strcpy (WEEK,"SATURDAY"); break;

printf ("\n this day is %s \( %d \)\n\n OK!\n",WEEK,week);

else

week=++week%7;

printf ("\n the calender of this month as following\n");

printf ("\n *********************************\n");

printf (" SUN MON TUE WEN THU FRI STA\n");

for (i=0;iweek;i++)

printf (" ");

for (i=1;i=month;i++)

printf (" %2d ",i);

week++;

if (week%7==0i!=month)

printf ("\n");

printf ("\n *********************************\n");

printf ("\n OK!\n");

这是一个万年历的小程序，效率不怎么高，不过涉及到很多基础知识，可以读读